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(y+2/y)^2+3y+6/y=4
We move all terms to the left:
(y+2/y)^2+3y+6/y-(4)=0
Domain of the equation: y)^2!=0
y!=0/1
y!=0
y∈R
Domain of the equation: y!=0We add all the numbers together, and all the variables
y∈R
(+y+2/y)^2+3y+6/y-4=0
We add all the numbers together, and all the variables
3y+(+y+2/y)^2+6/y-4=0
We calculate fractions
3y+((+y+2*y)/y^2*y)+6y/y^2*y)-4=0
We calculate terms in parentheses: +((+y+2*y)/y^2*y), so:We add all the numbers together, and all the variables
(+y+2*y)/y^2*y
We add all the numbers together, and all the variables
(+3y)/y^2*y
We multiply all the terms by the denominator
(+3y)
We get rid of parentheses
3y
Back to the equation:
+(3y)
6y+6y/y^2*y)-4=0
We multiply all the terms by the denominator
6y*y^2*y)-4+6y=0
Wy multiply elements
6y^4*y=0
We do not support eypression: y^4
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